I know that the base of the triangle is 14 metres, and the height of the triangle is 6 metres, so I can use the formula $\mathrm{A}=\frac{\mathrm{b}\times \mathrm{h}}{2}$ (base multiplied by height, then divided by 2).

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{\mathrm{b}\times \mathrm{h}}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{14\mathrm{m}\times 6\mathrm{m}}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{84{\mathrm{m}}^2}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}\mathrm{ }=\mathrm{ }42\mathrm{ }{\mathrm{m}}^2$

The area of the swimming pool is 42 m².

Before I begin my calculation, I know that each square is equal to 1 metre. Based on the shape of the parallelogram on the grid, I can estimate that the total area is approximately 16 m².

I can split the parallelogram shape into two triangles on each end, and a square. I can use the grid to help me calculate the height of each triangle since I know that 1 metre = 1 square.

Triangle A:

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{\mathrm{b}\times \mathrm{h}}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{3\mathrm{m}\times 2\mathrm{m}}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}=\frac{6{\mathrm{m}}^2}{2}$

$\mathrm{A}\mathrm{r}\mathrm{e}\mathrm{a}\mathrm{ }=\mathrm{ }3\mathrm{ }{\mathrm{m}}^2$

I can see that both triangles have the same area, so I can add $3\mathrm{ }{\mathrm{m}}^2+3\mathrm{ }{\mathrm{m}}^2=6\mathrm{ }{\mathrm{m}}^2.$

So, the total area of both triangles is 6 m².

Square: I know that to calculate the area of a square, I can multiply the two sides.

$3\mathrm{ }{\mathrm{m}}^2\mathrm{ }\times \mathrm{ }3\mathrm{ }{\mathrm{m}}^2=9\mathrm{ }{\mathrm{m}}^2$

Now, I can combine the area of the two triangles and square.

$6\mathrm{ }{\mathrm{m}}^2+\mathrm{ }9\mathrm{ }{\mathrm{m}}^2=15\mathrm{ }{\mathrm{m}}^2$

This gives me 15 m² as the total area of the parallelogram.