Minds On

Area and perimeter of my name

How would you create each letter of your name on graph paper?

Record your ideas in a notebook or a method of your choice.

How could you determine the total area and perimeter of all the letters combined? What strategies could you use?

Here is an example!

The word “Name” on graph paper. Room to write the area and perimeter of each letter underneath.

If you would like, you can complete the activity using TVO Mathify. You can also use your notebook or the following fillable and printable document.

Press the ‘TVO Mathify’ button to access this resource and the ‘Activity’ button for your note-taking document.

TVO Mathify (Opens in a new window) Activity(Open PDF in a new window)

To help you find the area and perimeter of your name, you may want a few tips. Press ‘Hint’ to reveal these tips.

Instead of using metric units, one grid square should equal one unit.

Each letter’s area will be the number of units in a letter.

Add up the units around the letter.

Action

Task 1: Calculating perimeter

What is perimeter?

Perimeter is the measurement of the outside lengths of a shape.

Consider some ways you can answer this example question: What is the rectangle’s perimeter?

Record your ideas in a notebook or a method of your choice. Side lengths this rectangle are: 16 cm, 16 cm, 4 cm, and 4 cm

When you are ready, press ‘Show Answer’ to reveal the solution.

To calculate the perimeter, you can add up all side lengths.

The equation to calculate perimeter side lengths on this rectangle adds 16 cm, 16 cm, 4 cm, and 4 cm

The perimeter of the rectangle is 40 centimetres.

Complete the activities with the following shapes. Record your answers in a notebook or a method of your choice. We will compare our answers after.

  1. What is the perimeter of the rectangle? How did you know what all the side lengths were of this shape, even though not all were labelled?

Press ‘Hints’ to reveal perimeter hints for a rectangle.

Opposite sides are equal and parallel in a rectangle.

The perimeter of a rectangle is two base lengths plus two side lengths.

A rectangle with a base length of 12.5 cm. The side length is 6.3 cm.
  1. What is the perimeter of this shape? How can you know even though not all side lengths are given? Press ‘Hint’ to reveal a perimeter hint for this arrow shape.

The seven-sided arrow is symmetrical in shape.
A seven-sided arrow with only 4 side lengths provided: 7cm, 5 cm, 5 cm, 1 cm.
  1. The total perimeter of the following rectangle is 48 cm. What are the lengths of the missing sides?
A rectangle with a base length of 16 cm.

When you are ready, press ‘Show Answer’ to reveal the solutions.

  1. 37.6 cm
  2. 31 cm
  3. 16 cm, 8 cm, and 8 cm

Task 2: Calculating area

When calculating area:

  • Area is defined as the size of a surface. It is the space inside of a two-dimensional shape.
  • The units are squared because area is calculated as a product of two dimensions.
  • There are different formulas for calculating the area of different shapes.

Area of parallelograms, squares, and rectangles

The formula to calculate the area of parallelograms, squares, or rectangles is:

Area = b × h

b = base

h = height

For the following questions, record your answers in a notebook or a method of your choice.

  1. How would you calculate the area of a rectangle with an 8 cm base and 4 cm height?
A rectangle with an 8 cm base and 4 cm height.

When you are ready, press ‘Show Answer’ to reveal the solutions.

Here is one way to do it.

A = b × h

= 8   cm × 4 cm

= 32 cm 2

Here is how the rectangle would look on a white board with the solution beneath it.

A rectangle with the label “8 cm” on top and “4 cm” on the left side. Underneath the shape, it says:

A = b × h

A = 8 × 4

A = 32 square centimetres

  1. Area of parallelogram is base × height. Calculate the area of the following parallelogram with 16 cm base and 10 cm height.
A parallelogram with a 16 cm base and 10 cm height.

Area of a triangle

The formula for calculating the area of a triangle is:

Area = b × h ÷ 2

This formula can be displayed in different ways:

  • Area = b × h ÷ 2
  • Area = 1 2 b × h
  • Area b × h 2

In what ways are these formulas the same? What is different about them? Which one do you prefer to use?

For the following questions, please record your calculations in a notebook or a method of your choice.

How would you calculate the area of the following triangle with base of 20 cm and height of 15 cm?

A triangle with a base of 20 cm and height of 15 cm.

When you are ready, press ‘Show Answer’ to reveal the solutions.

Here is one way to calculate the area of the triangle.

A triangle with a 20cm base and 15cm height. Its area is calculated to be 150 square centimeters.

Calculate the area of the following right triangle with 6 centimetres as base and height. Press ‘Hint’ to reveal a perimeter hint for this shape.

To calculate the area of triangle, we need the base and height, and not the hypotenuse (slant side).
A right triangle with a 6-centimetre base and height. The remaining side has no length listed.

Two methods for finding the area of a trapezoid

The following shape is an example of a trapezoid.

A trapezoid with four sides. It has a flat top and bottom, and 2 sloping sides.

What other shapes are within the trapezoid?

Using the information you already have about calculating the area of other shapes, how can you figure out the area of a typical trapezoid? There are many different ways to calculate the area of a trapezoid.

The trapezoid can be decomposed into rectangles, parallelograms, or triangles in different ways.

Here are 2 ways to calculate the area of a trapezoid.

Trapezoid area method 1

Break up the original trapezoid into 2 triangles and 1 rectangle.

A trapezoid with an arrow beside the shape, pointing up and down, with the word “Height” in the middle. Below the shape, there are arrows indicating Base 1 of the first triangle, Base 2 of the centre rectangle, and Base 3 of the second triangle.

A trapezoid can be divided into 2 triangles and 1 rectangle.

  • The formula is: area of triangle 1 (left side) + area of rectangle + area of triangle 2 (right side).

Here is an example of how this method could be used.

A trapezoid that has been decomposed into a triangle on left, a rectangle in centre, and a triangle on right. There is an arrow beside the shape, pointing up and down, indicating that the height is 5 cm. The shape base 1 is 3 cm, base 2 is 6 cm, and base 3 is 3 cm.

Area = area of triangle 1 + area of rectangle + area of triangle 2.

= (3 × 5 ÷ 2) + (6 × 5) + (3 × 5 ÷ 2)

= 7.5 + 30 + 7.5

= 45 cm²

Trapezoid area method 2

Double the original trapezoid so it becomes a parallelogram. Find the area of the parallelogram and then divide it by 2.

A trapezoid has been reflected vertically and attached to the original trapezoid, creating a parallelogram. There is a vertical arrow beside the new shape labelled “Height.” Below the shape, there are arrows indicating Base 1 of the first trapezoid, and Base 2 of the second trapezoid. Finally, there is the formula ( b 2 + b 2 ) × ÷ 2 . In other words: (Base 1 of first trapezoid (b1) plus Base 2 of second Trapezoid (b2)) × height of trapezoid h and divide by 2.

The diagram has two identical trapezoids, with one inverted, which have been put together to create a parallelogram.

The formula is b 1 + b 2 × h ÷ 2.

In other words: (Base 1 of first trapezoid b 1   plus Base 2 of second Trapezoid b 2   ) × height of trapezoid h and divide by 2.

Here is an example of what this would be.

A trapezoid has been reflected vertically and attached to the original trapezoid, creating a parallelogram. There is a vertical arrow beside the new shape indicating the height is 15 cm. For the first trapezoid, the base 1 is 15 cm, and for the second trapezoid, the base 2 is 3 cm.

Area = b 1 + b 2 × h ÷ 2

= 15 + 3 × 15 ÷ 2

= 18 × 15 ÷ 2

= 135   c m 2

Find the trapezoid area

If you would like, you can complete the next activity using TVO Mathify. You can also use your notebook or the following fillable and printable document. Choose one of the methods outlined earlier in this learning activity. Calculate the area of a trapezoid with the following dimensions. The base is 16 cm, height is 12 cm, and the top is 10 cm.

A trapezoid with a base of 16 cm, a height of 12 cm, and a 10cm top.

Press ‘Hint’ to reveal a perimeter hint for this shape.

Decompose the trapezoid into two triangles and one rectangle.

Press the ‘TVO Mathify’ button to access this resource and the ‘Activity’ button for your note-taking document.

When you are ready, press ‘Show Answer’ to reveal the solutions.

(Area of Triangle 1) + (Area of Rectangle) + (Area of Triangle 2)

(12 × 3 ÷ 2) + (12 × 10) + (12 × 3 ÷ 2)

18 + 120 + 18 = 156 cm2

A method for finding the area of a rhombus or a kite

The following diagram is a rhombus and a kite. In a rhombus, the diagonal (interior, blue) lines are equal, but in a kite, the diagonal lines are not equal.

 A rhombus and a kite

What other shapes are within a rhombus or kite? Inside, you may notice four triangles: a pair of similar triangles on top, and a pair on the bottom. You could find the areas of the interior four triangle to get the area. However, there is a faster way. What if you used the diagonal (interior, blue) lines to form a rectangle around the kite or rhombus, as shown in the following diagram. You will now notice 4 interior and 4 exterior triangles.

A kite inscribed within a square.

The area of the four triangles outside the kite is equal to the area inside the kite. Therefore, the area of the kite (the four triangles) is half the area of the entire square (the eight triangles).

In other words, the formula for the area of a kite is: (length × width) divided by two.

How would you use this information to calculate the area A  of a kite that is measured 20 centimetres in one diagonal p , and 30 centimetres in the other diagonal q ? Here is one way to find the area of this kite.

A kite with interior diagonal (p) lines measuring 20 centimetres, and another diagonal (q) measuring 30 centimetres. The kite’s area equals (p times q) divided by 2. When you substitute the diagonal measurements, you get (20 times 30) divided by 2. This equals an area of 300 square centimetres for the kite.

Area = p × q ÷ 2

Area = 20 × 30 ÷ 2

Area = 600 ÷ 2

Area = 300 c m 2

The area of this kite is 300 c m 2 .

Task 3: Area and perimeter in real-life

Why is it relevant to understand how to calculate the area and perimeter of something?

Here are some instances when someone would need to calculate the area and perimeter of something:

  • building a fence around a garden
  • building a swimming pool
  • creating a floor plan

Can you think of other instances?

Record your ideas in a notebook or a method of your choice.

Blueprint plan for a backyard pool and deck.

Task 4: Calculating perimeter and area for irregular shapes

An irregular shape is any shape that has sides and angles that can be any size or length.

They do not have to be equal.

Challenge: Create any irregular shape. Use digital or concrete manipulatives.

Describe the shape. Record your ideas in a notebook or a method of your choice.

Perimeter of irregular shapes

In order to calculate the perimeter of irregular shapes, we follow the same instructions as a regular shape. Add up all side lengths to find the perimeter.

Consider

How might you calculate the perimeter of this irregular shape?

An irregular shape with 3 sides that are the same length of 3 centimetres. The top side is 5 centimetres and the remaining side is 7 centimetres.

Press ‘Hint’ to reveal a perimeter hint for this shape.

Perimeter is the sum of all sides of a shape.

Area of irregular shapes

In order to calculate the area of irregular shapes, we begin by dividing it into smaller, known shapes. Consider the following irregular shape.

An irregular shape made of a large rectangle with a small square jutting out from the upper right-hand corner. The base of the shape is 10cm, the left side is 6cm, and the top and one side of the squared section are 2cm.

Let’s calculate the area of the irregular shape.

Step 1: Divide your irregular shape into smaller, known shapes.

For this shape we can divide it into 1 square and 1 rectangle.

An irregular shape that has been split up into a 6 by 10 rectangle and a 2 cm by 2 cm square. The left side of the rectangle is 6 cm. The bottom (base of the rectangle) is 10 cm. The top of the square is 2 cm.

Step 2: Find the area of each smaller shape.

For this shape, we will find the area of the square and the rectangle.

Square:

Area = 2 × 2

= 4   c m 2

Rectangle:

Area = 6 × 10

= 60   c m 2

Step 3: Add all of the areas together.

4   c m 2 + 60   c m 2 = 64   c m 2

Area = 64   c m 2

Task 5: Your turn!

Examine and solve each of the problems. Show your work and record your calculations in a notebook or a method of your choice. When you are ready, press ‘Show Answer’ to reveal a solution.

  1. Find the area of the shape. Press ‘Hint’ to reveal a perimeter hint for this shape.

Decompose the trapezoid into two triangles and one rectangle.
A 5-sided irregular shape with sides of 2 cm, 10 cm, 5 cm, 5 cm, and a side of unknown length.

Solution: Divide your irregular shape into smaller, known shapes.

For this shape, we can divide it into 1 square, 1 rectangle, and 1 triangle.

Area of square plus area of rectangle plus area of triangle.

Area of the shape is (5 × 5) + (5 × 2) + (3 × 5 ÷ 2) = 42.5 cm

  1. Find the area and perimeter of the shape.
An irregular shape split into a 1 by 10 rectangle, and a triangle with side lengths of 4, 10 and 11.

Solution: Divide your irregular shape into smaller, known shapes.

For this shape, we can divide it into 1 rectangle and 1 triangle.

Area of rectangle plus area of triangle.

Area of the shape: (10 × 1) + (4 × 10 ÷ 2) = 30 cm

Perimeter: 10 + 1 + 5 + 11 = 27 cm

  1. Find the area of the shape given.
A trapezoid made of a 3 by 3 square, a 3 by 2 right triangle, and a 5 by 3 right triangle.

Solution: Divide your irregular shape into smaller, known shapes.

For this shape, we can divide it into one triangle on left, one rectangle in centre, and one triangle on right.

Area of the shape: (3 × 2 ÷ 2) +(3 × 3) +(3 × 5 ÷ 2) = 19.5cm2

Consolidation

Task 1: Home design

Floor plan of a house without measurements.

A contractor has been tasked with creating a house. Let’s create a floor plan of what the house could be like.

The contractor also has a set of criteria to follow. The house must have rooms that are each of these shapes:

  • rectangle
  • square
  • triangle
  • trapezoid
  • at least one irregular shaped room
  • whatever other shapes you would like!

You will need to:

  • create a floor plan for this home (each room, hallways, etc.)
  • calculate the area and perimeter of each room
  • calculate the area and perimeter of the home as a whole
  • show your work to explain how you calculated each area and perimeter

Record your ideas in a notebook or a method of your choice.

Task 2: Questions to explore

Reflect on and answer the following questions:

  • How do you think area and perimeter are related to each other?
  • What was the least common shape found when you decomposed irregular shapes to calculate area and perimeter? What was the most common shape?

Record your ideas in a notebook or a method of your choice.

a castle with the first floor as a rectangular prism, the second floor being a cube with a triangular prism roof and a cylinder with a cone roof

Reflection

As you read through these descriptions, which sentence best describes how you are feeling about your understanding of this learning activity? Press the button that is beside this sentence.

I feel...

Now, record your ideas using a voice recorder, speech-to-text, or writing tool.

Connect with a TVO Mathify tutor

Think of TVO Mathify as your own personalized math coach, here to support your learning at home. Press ‘TVO Mathify’ to connect with an Ontario Certified Teacher math tutor of your choice. You will need a TVO Mathify login to access this resource.

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